Joslin's terrestrial and celestial globes

and Celestial

277
J83
1885
NMAH

deSLiN'S HAND-B00K

317
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HOW TO USE A GLOBE.

JOSLIN'S

TERRESTRIAL AND CELESTIAL

GLOBES.

AUG_0^JS91

i/BRARlES

GILMAN JOSLIN & SON,

Manufacturers and Dealers, 5 Mt. Vernon Ave.,
BOSTON, MASS.

USEFULNESS OF GLOBES.

The importance of globes, both as articles of school and
household furniture, has long been greatly under-estimated.

Until within a few years they were to be found, with rare
exceptions, only among our colleges and leading academies,
with occasionally one in some public or private library, and
were regarded almost in the light of a curiosity by the large
mass of people.

In these days of popular education, however, the import-
ance and necessity of their use in framing correct ideas in the
minds of children at the outset, together with their value for
subsequent reference and study, has become much more
widely recognized, and has led to their general introduction
into schools of all grades.

It is an important fact in favor of such general introduction
that almost all children and many grown people manifest
intense interest and surprise when they see a globe for the
first time. They then seem to drink in at once an entirely
new idea of the correct shapes and true relative positions of
the various countries, their false notions of which have been
produced by the exclusive study of maps printed on flat sur-
faces, and which are, on that account, necessarily somewhat
incorrect.

As a matter of fact, the presence of a globe in the school-
room, even though not a single lesson be given upon it, has
been found to be of the greatest assistance ; for, having it
constantly before them, the scholars acquire many and cor-
rect ideas which could not be gathered from books, the im-

4 JOSLINS GLOBES.

p cessions from which are of valuable and lasting service to
them.

As an example of the increased consideration now being
given to this subject, we may say that the City of Boston,
whose schools are universally conceded to be among the fore-
most in this country, has recently purchased for their use
one or more of Joslins Globes for every school-room above the
primary grade throughout the city. Moreover, the Joslin
Globe was selected after a critical examination by the Com-
mittee of all globes in the market.

For library or office use a globe is no less valuable, showing,
as it does at a glance, the true relative situations of Political
and Geographical Divisions, Cities, etc., the world over.

Some of the advantages of these globes are : They may be
depended upon as accurate, the plates having lately been
revised to correspond with all recent political changes. All
the maps are printed directly from copper plates, and are not
lithographed. The meridians are accurately graduated. The
varnish is warranted not to crack or peel off, a common failing.
The stands are thoroughly and firmly fitted together, and the
general workmanship throughout is of the first order.

Finally, it will be our constant endeavor to maintain the
reputation which our globes have long enjoyed for superior
accuracy, durability, and beauty, and to merit on that account
a liberal share of public patronage.

With these few introductory remarks upon the general
usefulness and importance of the globe, we will proceed to
describe how to use a globe in the working of problems, etc.

GILMAN JOSLIN & SON.

JOSLINS GLOBES.

HOW TO USE A GLOBE.

1. A Terrestrial Globe is a ball or sphere, representing the
earth. Upon its surface are drawn the natural divisions of
land and water, — continents, islands, capes, mountains,
oceans, lakes, bays, rivers, etc. ; it also represents the political
•divisions of countries, and the lines of latitude and longitude.

2. The Axis of the earth is represented by the iron rod
which passes through the centre of the globe, and upon which
it turns.

3. The Poles of the earth are the two ends of the axis ; one
is called the North or Arctic Pole, and the other the South
or Antarctic Pole.

4. The Equator is a circle passing around the globe at equal
distances from the poles. It divides the globe into the North-
ern and Southern hemispheres.

5. The Equinoctial is the equator extended to the heavens.
When the sun is crossing the equinoctial, the days and nights
are equal all over the world.

6. All Circles on the globe are supposed to be divided into
360 equal parts, called degrees.

7. The Brass Meridian is the circle of brass within which
the globe turns on its axis. One half of this meridian is
graduated from the equator to the poles; that is, the point
over the equator is 0, and the point over the poles is 90 ; this
enables us to find the latitude of a place. The other half is
from 0 at the poles to 90 at the equator ; this is so that we
can elevate the pole to the latitude of the place.

8. Meridians of longitude are semicircles extending from
pole to pole, and cut the equator at right angles. Beginning
at Greenwich, which is called the first meridian, there is on
the globe a meridian every 15 degrees ; these correspond to
the hours of time, dividing the globe into 24 equal parts.

6 joslin's globes.

9. The Longitude of a place is the distance of the meridian
passing through it from the first meridian, reckoned in degrees
on the equator. Longitude is either east or west, according
as the place is east or west of the first meridian. The figures
on the north side of the equator express the degrees of longi-
tude, and are reckoned from Greenwich east and west from 0°
to 180°. The Roman letters on the south side of the equator
represent the hours of time, and correspond to the degrees
of longitude. The figures between the letters express the
minutes of time. The edge of the brass meridian is used for
drawing a meridian through any place.

10. Parallels of Latitude are small circles parallel to the
equator, and on the globe are drawn at distances of 10 degrees
from each other.

11. The Latitude of a place is its distance north or south
of the equator, reckoned in degrees on the brass meridian.

12. Parallels of Celestial Latitude are small circles drawn on
the celestial globe parallel to the ecliptic.

13. Parallels of Declination are small circles parallel to the
equinoctial on the celestial globe, and are similar to parallels
of latitude on a terrestrial globe.

14. The Tropics are two small circles parallel to the equator,
23 2 degrees from it. The northern is called the Tropic of
Cancer, and the southern the Tropic of Capricorn.

15. The Polar Circles are two small circles parallel to the
equator, and 23 2 degrees from the poles. The northern is
the Arctic circle, and the southern is the Antarctic.

16. The Zones. The surface of the earth is divided by the
tropics and polar circles into five parts, called zones. The
part lying between the tropics of Cancer and Capricorn is
called the Torrid Zone ; between the tropic of Cancer and the
Arctic circle, the North Temperate Zone ; between the tropic
of Capricorn and the Antarctic circle, the South Temperate

JOSLIN S GLOBES. 7

Zone; between the Arctic circle and the North pole, the
North Frigid Zone ; between the Antarctic circle and the
South pole, the South Frigid Zone.

17. The Ecliptic is a great circle representing the sun's
apparent path throughout the year. It touches the tropics of
Cancer and Capricorn, and is inclined to the equator at an
angle of 23 1 degrees. The two points where it crosses the
equator are called the Equinoctial Points.

18. The Signs of the Zodiac. The ecliptic is divided into
twelve parts of 30 degrees each, called Signs of the Zodiac,
each having a particular name and character by which it is
designated. There are six northern and six southern ones.
The sun appears in the former in our spring and summer
months, and in the latter during our autumn and winter
months. The days on which the sun enters the different signs
are as follows : —

Northern Signs of the Zodiac
Spring Signs. Summer Signs.

Aries, the Ram, March 21. Cancer, the Crab, June 21.

Taurus, the Bull, April 20. Leo, the Lion, July 23.

Gemini, the Twins, May 21. Virgo, the Virgin, August 23.

Southern Signs of the Zodiac.
Autumnal Signs. Winter Signs.

Libra, the Balance, Sept. 23. Capricornus, the Goat, Dec. 22.

Scorpio, the Scorpion, Oct. 23. Aquarius, the Waterman, Jan. 20.

Sagittarius, the Archer, Nov. 23. Pisces, the Fishes, Feb. 19.

19. The Equinoctial Points where the equator crosses the
ecliptic are Aries and Libra ; the former is the Vernal and
the latter the Autumnal equinox. When the sun is in either
of these points, the days and nights are equal all over the
world.

20. The Solstitial Points are the points where the ecliptic
touches the tropics of Cancer and Capricorn. When the sun

8

enters Cancer, it is the longest day in the northern and the
shortest in the southern hemisphere. On the contrary, when
the sun enters Capricorn, it is the shortest day in the northern
and the longest in the southern hemisphere.

21. The Comres are two great circles passing through the
poles. The equinoctial colure passes through the equinoctial
points ; the other, the solstitial colure, passes through the
solstitial points.

22. The Zenith is the point in the heavens directly over
our heads.

23. The Nadir is the point in the heavens directly below
our feet.

24. Antipodes are the people who live on opposite sides of
the earth, and walk feet to feet. Their latitudes, longitudes,
days and nights, seasons, are exactly contrary to each other.

25. There are two Horizons ; the sensible or visible horizon,
and the rational or true horizon.

26. The Sensible Horizon is that circle in the earth which
bounds our view.

27. The Kational or True Horizon is a great circle of the
heavens, everywhere 90 degrees from the zenith.

28. The Altitude of an object in the heavens is its distance
from the horizon. When the body is on a meridian, such as
the sun at noon, its altitude is then called meridian altitude.

29. The Zenith Distance of a celestial body is its distance
from the zenith.

30. The Quadrant is a thin, flexible strip of brass, divided
upward from 0 to 90 degrees, and downward from 0 to 18
degrees. It can be screwed to the brass meridian. The
upper part is used for finding distances between places on the
earth, the altitude of heavenly bodies, etc., and the lower for
finding the length of twilight.

31. Almacanters or Parallels of Altitude are imaginary circles

joslin's globes. 9

parallel to the horizon, and serve to show the height of the
sun, moon, and stars. The circles are not drawn on the globe,
but they may be described for any latitude by the quadrant
of altitude.

32. Azimuth or Vertical Circles are great circles passing
through the zenith and nadir points, cutting the horizon at right
angles. The altitudes of the heavenly bodies are measured
on these circles. This is done by screwing the quadrant of
altitude on the zenith of the place of observation, and moving
the slip of brass until its graduated edge passes through the
body.

33. The Azimuth of any celestial body is an arc of the
horizon lying between a vertical circle passing through the
body and the north or south points of the horizon.

34. The Amplitude of any celestial body is the distance
at which it rises from the east or sets from the west.

35. The Wooden Horizon, surrounding the artificial globe,
represents the rational horizon. It is usually divided into
seven concentric circles : the first is for finding the amplitude
of heavenly bodies ; the second for finding their azimuth;
the third contains the thirty-two points of the compass; the
fourth contains the twelve signs of the zodiac, with the degrees
of each sign ; the fifth contains the days of the month, corre-
sponding to every degree of the sun's place in the ecliptic,
as indicated in the fourth circle ; the sixth contains the equa-
tion of time, that is, the difference of time between a clock
and a sun-dial; the seventh contains the twelve calendar
months.

36. The Hour Circle is a flat brass circle turning on the
axis of the globe at the pole, and under the brass meridian.
It is divided into 24 equal parts representing hours. It is
used for finding the difference of time between places, the
length of the days, etc. On some globes the hour circle is.

10 joslin's globes.

drawn around the pole, and has a brass index which is
attached to the axis.

37. The Declination of the sun is its distance north or south
of the equinoctial. At the equinoxes it has no declination.
At the tropic of Cancer it has its greatest northern declination,
and at the tropic of Capricorn, its greatest southern declination.

38. The Eight Ascension of the sun is the distance of the
meridian passing through the sun's place in the ecliptic, from
the equinoctial point Aries, reckoned in degrees eastward
on the equator or equinoctial.

39. The Analemma is a diagram resembling the figure 8.
It is a scale drawn on the terrestrial globe from one tropic to
the other, showing the sun's declination on any day in the
year. It contains the months and days and signs of the
zodiac, and shows the equation of time, that is, the difference
between clock-time and that of the sun-dial.

PKOBLEMS ON THE TERKESTKIAL GLOBE.

Problem I. To find the latitude and longitude of any
given place.

Rule. Bring the given place to the graduated edge of the metallic
meridian ; the degree directly over the place is the latitude. The degree
on the equator cut by the metallic meridian is the longitude.

EXAMPLES.

What is the latitude and longitude of the following places?

New York. Answer: Lat. 41° N. Long. 74° W.

San Francisco. "

Calcutta.

Rio Janeiro. "

Quito.

37° N.

" 122° W.

23° N.

" 89° E.

23° S.

" 43° W.

0°

" 79° W.

joslin's globes. 11

The latitude of the north and of the south pole is 90°.
The longitude of the poles is 0°. 90° is the highest latitude
that any place can have. 180° is the highest longitude that
any place can have. All places on the equator have no
latitude. All places on the first meridian have no longitude.

Problem II. To find any place on the globe having its
latitude and longitude given.

Rule. Find the given longitude on the equator, and bring it to the
metallic meridian. Find the given latitude on the metallic meridian,
and the place immediately under will be the place required.

EXAMPLES.
What places have about the following latitudes and longi-
tudes?

33° S.

72° W.

Answer

: Valparaiso.

9°N.

80° W.

"

Panama.

42° N.

88° W.

"

Chicago.

19° N.

100° w.

u

Mexico.

35° N.

140° E.

((

Yokohama.

Problem III. To find all those places which have the
same latitude as a given place.

Rule. Bring the given place to the metallic meridian, and find its
latitude. Turn the globe slowly round, and all places which pass under
the observed latitude will be the ones required.

EXAMPLES.
What places have about the same latitude as Boston ?

Answer: Albany, Buffalo, Chicago, Omaha, Constanti-
nople, Rome, Marseilles.

All places in the same latitude have the same seasons and
the same length of day and night ; but, owing to various

12 joslin's globes.

physical causes (such as the adjoining land and water), they
may not have the same climate.

Problem IV. To find all those places which have the
same longitude as a given place.

Rule. Bring the place to the metallic meridian. All places under
the edge of the metallic meridian, from pole to pole, have the same
longitude.

People living in the same longitude have noon and all of
the hours of the day alike ; their clocks all agree ; but they
all have sunrise and sunset at different hours from one
another, depending on their latitude.

EXAMPLES.

What places have about the same longitude as Copenhagen ?
Answer : Berlin, Venice, Rome, Palermo, Tripoli, mouth
of the Congo River.

What people have nearly the same time as the people of
Massachusetts ?

Answer: Those in Quebec, Hayti, Venezuela, Colombia,
Ecuador, Peru, and Chili.

Problem V. To find the distance between two places.

Rule. Lay the edge of the quadrant of altitude over the two places,
so that the point marked 0 may be over one of them; the number of
degrees over the other place will be the number of degrees they are
apart. Multiply the number of degrees by 60 for the geographical miles,
or by 69& for the English or statute miles. Or take the distance between
the two places with a thread ; apply that distance to the equator ; this
will show the number of degrees in the distance ; then multiply as before
for the miles.

joslin's globes. 13

examples.
What is the distance between

Degrees. Geog. Miles. Eng. Miles.

Portland and San Francisco ? Answer : 39 \ 2370 2732
London " Constantinople? " 22 1320 1522

Liverpool " Cairo? " 34 2040 2352

Problem VI. The hour of the day being given at one
place, to find what hour it is at any other place.

Rule. Bring the place at which the time is given to the metallic
meridian ; turn the hour circle until the given hour comes to the metallic
meridian, or set the hour index to the given hour ; turn the globe until
the other place comes under the metallic meridian, and the hour on the
hour circle, which is under the metallic meridian or under the index,
will be the time required.

Or thus by calculation.

Rule. Find the difference in longitude between the two places,
allow an hour for every 15 degrees and 4 minutes for every degree, and
the time thus obtained will be the difference of time between the two
places. If the place at which the time is required lies to the east of the
given place, this difference of time must be added to find the time at the
place required ; but if it lies to the west, it must be subtracted.

EXAMPLES.

When it is 3 o'clock in the afternoon at London, what time
is it at St. Petersburgh ?

Answer: 5 o'clock in the afternoon.
Or by calculation. The difference in longitude is 30° ;
divided by 15 gives just 2 hours difference of time.
St. Petersburgh being east of London, this 2 hours
must be added to the London time, which gives us
5 o'clock in the afternoon.

14 joslin's globes.

When it is 2 o'clock in the afternoon at Cairo, what time is
it at New York ?

Answer : 7 o'clock in the morning.
By calculation. Longitude, Cairo, 31° E.

New York, 74° W.

Difference of longitude, 105°, divided by
15 gives 7, the difference in hours.

New York being west of Cairo, these 7 hours must be
subtracted from Cairo time, and 7 from 2 o'clock in the
afternoon is 7 o'clock in the morning.

Problem VII. The time of any two places, and one of the
places being given, to find the longitude of the other place.

Rule. Bring the given place to the metallic meridian, set the hour
index at the given hour of the place, turn the globe until the other given
hour comes under the metallic meridian, and the degree on the equator
cut by the metallic meridian will be the longitude.

Or by calculation.

Rule. Allow 15° difference of longitude for every hour of time, or
1° for every 4 minutes of time.

EXAMPLES.

When it is 4 o'clock in the afternoon at a certain place, it
is noon at London ; required the longitude of the place.
Answer : 60° east longitude.

By calculation. 4 hours of time, at 15° for each hour,
gives 60°, the difference of longitude. As the hour at
London is earlier than at the other place, it follows
that the place must be 60° to the east of London ; or,
as London has 0° for longitude, the place must have
60° east longitude.

joslin's globes. 15

When it is noon at Boston, at what places is it 10 o'clock
in the morning.

Answer: All places in longitude 100° west, as the
middle of Nebraska, Kansas, Texas, and the city of
Mexico.

Problem VIII. To find the length of a degree in any
given parallel of latitude.

Rule. Lay the edge of the quadrant of altitude along the given
parallel; take the number of degrees upon it intercepted between any
two meridians (15° apart), and that number multiplied by 4 will give
the number of geographical miles contained in a degree of the given
parallel. To find the number of English miles, multiply the number of
degrees by 69^, and divide by 15, or, what is the same thing, multiply
the number of degrees by 4.6.

EXAMPLES.

How many geographical and English miles are there in a
degree on the 50th parallel of latitude ?

Answer : The distance between two meridians 15° apart
on the 50th parallel is 9f° of the equator.
9f X 4 =39 geographical miles.
9| x 4.6 = 44.85 statute miles.

What is the length of a degree on the parallel of 30° ?
Answer : 15° parallel of 30° = 13° on the equator.
13 X 4 =52 geographical miles.
13 x 4.6 = 59.8 statute miles.

Problem IX. To find the Antipodes of a given place.

Rule. Bring the given place to the metallic meridian ; set the index
of the hour circle at 12, or bring 12 on the hour circle to the metallic

16 joslin's globes.

meridian ; turn the globe half round, or until the index points to the
other 12 ; then, under the same degree of latitude with the given place,
but in the opposite hemisphere, will be the place of the Antipodes.

EXAMPLES.

Required the Antipodes of the following places : —

London. Answer: Antipodes Island, near New Zealand.

Spain. " New Zealand.

Chili. " China.

Bermudas Islands. " South-west part of West Australia.

Problem X. To "rectify the globe for any given place.

Rule. Elevate or raise the north or south pole as many degrees
above the wooden horizon as are equal to the latitude of the place, and
bring the given place to the metallic meridian. If the given place is in
north latitude, the north pole must be elevated ; if in south latitude, the
south pole. In elevating either pole, the degrees must be counted from
the pole to be elevated toward the equator.

EXAMPLES '

Rectify the globe for Boston.

Boston is in latitude 42 \° north; therefore elevate the
north pole 42£° above the wooden horizon, and turn the globe
until Boston comes to the edge of the metallic meridian.

Rectify the globe for Rio Janeiro.

Rio Janeiro is 23 j° south latitude. Elevate the south pole
23 2° above the wooden horizon, and turn the globe until Rio
Janeiro comes to the edge of the metallic meridian.

Note. When the globe is rectified for any place, the place is in the
zenith of the globe ; that is, it is everywhere 90° from the wooden hori-
zon, and the wooden horizon becomes the true horizon of the place.

joslin's globes. 17

Now, if the stand of the globe is made to occupy a horizontal position,
and the north and south points of the wooden horizon are made to cor-
respond with the north and south points of the compass, the globe is
said to be set. In this position the axis of the globe is parallel with the
axis of the earth, the equator of the globe to the equator of the earth,
the parallels of the globe to the parallels of the earth ; and the globe
may be turned, so that the ecliptic on the globe shall be parallel to the
ecliptic in the heavens on any day in the year.

Problem XI. To find the suns place in the ecliptic
for any given day.

Rule. Find the month, and the mark corresponding to the day of
that month, in the outer circle of the wooden horizon ; then the coin-
cident mark in the circle containing the signs of the zodiac will give the
sun's place in the ecliptic, which may then be found upon the globe.

In Joslin's Globes the ecliptic is divided also into the months and
the days of the month, so that any required day may be found directly
on the ecliptic.

Problem XII. To find the suns declination for any given
day, and also to find the places to which the sun will be
vertical on that day.

Rule. Find the sun's place in the ecliptic for the given day ; bring
that point in the ecliptic to the metallic meridian, and the degree directly
over it on the metallic meridian is the declination, north or south. Turn
the globe around, and every place which passes under that degree of the
metallic meridian will have the sun vertical on that day.

The declination of the sun gives the latitude of the places which will
have the sun vertical on that day. The sun can be vertical only to
places within the torrid zone.

Or the declination may be found by bringing the given day on the
analemma to the metallic meridian, and the degree on the meridian
over the day on the analemma will be the declination.

18 joslin's globes.

examples.

What is the declination of the sun on the 21st of June, and
what is the latitude of the places that will have the, sun
vertical on that day ?

Answer: 23 1° North Declination.
23 J° North Latitude.

What is the sun's declination on the following days?
Sept. 12. Answer: 4J° North Declination.
Dec. 10. " 22i° South

Jan. 1. " 23° South

April 15. " 10° North

Problem XIII. To find the hour at which the sun rises
and sets at a given place, for any given day. Also, to find the
amplitude of the sun for that day.

Rule. Rectify the globe for the latitude of the place by Problem X.
Find the sun's place in the ecliptic, and bring it to the metallic meridian.
Set the index of the hour circle at 12. Turn the globe until the sun's
place comes to the eastern edge of the wooden horizon, and the index
will then show the hour at which the sun rises; then turn the globe
until the sun's place comes to the western edge of the wooden horizon,
when the index will show the hour at which the sun sets.

Remark. 1. The length of the day is found by doubling the hour
of sunset.

2. The length of the night is found by doubling the hour of sunrise.

3. To find the amplitude of the sun, observe the degree of amplitude
on the wooden horizon, which is cut by the sun's place in the ecliptic
at the time of rising or setting.

EXAMPLES.

At what time will the sun rise and set at London on the
21st of December? What is the length of the day and night
at that time, and what is the amplitude of the sun?

joslin's globes. 19

Answer: The sun rises at i past 8.
The sun sets at \ before 4.
Length of day, 7£ hours.
Length of night, 16£ hours.
Sun's amplitude, 39° south of east.

What is the length of the longest day at St. Petersburgh ?
How far from the east point of the horizon does the sun rise
on that day?

Answer : Length of day, 18? hours.

Sun's amplitude, 52° north of east.

What is the length of the shortest day in New York ?
Answer : Length of day, 9 hours.

Show that the day is always 12 hours long at the equator.

Show that the 21st of June is the longest day to the people
of the northern hemisphere, and that the 21st of December
is their shortest.

Problem XIV. To find the suns meridian altitude at a
given place on a given day.

Rule. Rectify the globe for the latitude of the place ; bring the
sun's place in the ecliptic for the given day to the metallic meridian ;
count the number of degrees on the metallic meridian, between the sun's
place and the wooden horizon, for the meridian altitude required.

Or thus : Find the declination of the sun for the day, and add to it
the co-latitude of the place when the declination and the co-latitude are
of the same name, but subtract it when they are of different names.

EXAMPLES.
What is the sun's meridian altitude at Boston on the 21st
of June?

Answer : 71°. This is the greatest elevation of the sun
above the horizon at Boston.

20 joslin's globes.

By calculation. The latitude and declination are both
north. The declination of the sun on this day is 23J°
north, and the co-latitude is 90°— 42i° = 47i°; there-
fore the meridian altitude is 23J° + 47i° = 71°.
What is the sun's meridian altitude at Boston on December
21?

Answer: 24°. This is the least meridian altitude of the

sun to the people of Boston.
By calculation. Here the declination is south and the
latitude north, therefore we have the meridian altitude
47J°- 23J°=24°.
What would be the meridian altitude of the sun on the
21st of June at the following places ?
North Pole. Answer: 23|°.
Arctic Circle. " 47°.

Equator. 66 £°, or 23 i° from the zenith.

Problem XV. To find the suns altitude and azimuth
at any given place on any given day and hour.

Rule. Rectify the globe for the latitude of the place ; bring the
sun's place in the ecliptic to the metallic meridian ; set the index at 12 ;
turn the globe until the index points to the given hour ; fix the quadrant
of altitude on the metallic meridian, at the degree of latitude of the
given place, and lay its graduated edge over the sun's place ; then count
the number of degrees on the quadrant between this point and the wooden
horizon, and it will give the altitude required. The number of degrees
on the wooden horizon, counting from the north or south point of it, to
the point where the graduated edge of the quadrant cuts it, will be the
azimuth.

EXAMPLES.

What is the sun's altitude and azimuth at London on the
5th of May at 7 o'clock in the morning?
Answer: Altitude, 211°.

Azimuth, 90° from the north.

joslin's globes. 21

What is the sun's altitude and azimuth at St. Petersburgh
on July 2 at 4 p.m.

Answer: Altitude, 35°.

Azimuth, 75° from the south.

Problem XVI. The hour and day at any particular
place being given, to find the place where the sun is then
vertical.

Rule. Find the sun's declination of the given day (Problem XII.) ;
bring the given place to the metallic meridian ; set the index to the given
hour ; turn the globe until the index points to 12 noon. The place
under the metallic meridian whose latitude is the same as the sun's
declination will have the sun vertical at the hour given. This also
shows that all places under the metallic meridian will have noon at the
same time.

EXAMPLES.

To what place will the sun be vertical on the 7th of
January when it is \ to 3 in the afternoon at London ?
Answer : Rio Janeiro.
To what place will the sun be vertical when it is 2 o'clock
in the afternoon of May 15 at Boston?
Answer: City of Mexico.

Problem XVII. To find the two days in the year in which
the sun will be vertical to any given place in the torrid zone.

Rule. Bring the given place to the metallic meridian, and observe
its latitude. Bring the analemma to the metallic meridian, and the two
days on it that come under that latitude are the days required.

EXAMPLES.
On what two days of the year will the sun be vertical at
Aspinwall ?

Ansiuer : April 2 and August 30.
On what two days will the sun be vertical at Calcutta ?
Answer : June 10 and July 4.

22 joslin's globes.

Problem XVIII. The hour and day at a particular place
being given, to find the places where the sun is then rising or
setting ; and also places where it is noon or midnight.

Rule. Find the sun's declination for the given day; elevate the
north or south pole (according as the sun's declination is north or south)
as many degrees above the wooden horizon as are equal to the sun's
declination ; bring the given place to the metallic meridian, and set the
index to the given hour ; turn the globe until the index points to 12
noon. Then to all places above the wooden horizon it will be day, and
to all places beneath it it will be night ; all places on the western edge
of the wooden horizon will have the sun rising, and all places on the
eastern edge will have it setting ; all places under the upper half of the
metallic meridian will have noon, and all those under the lower half
will have midnight. All places not more than 18° below the western
edge of the horizon will have morning twilight, and all places not more
than 18° below its eastern edge will have evening twilight.

EXAMPLES.
When it is 8 o'clock in the morning at Boston on the 23d
of June, where is the sun rising and setting? and where is it
noon and where midnight ?

Answer: The sun is rising at San Francisco and the
Pacific coast States, the southern part of Chili, and at
Patagonia ; it is setting at Calcutta, the middle of th.e
Chinese Empire, and the eastern part of Siberia. It
is nearly noon at Ireland, Portugal, and the extreme
western part of Africa ; it is midnight at the Loyalty
Islands and New Zealand.
When it is 4 o'clock in the afternoon at London on the
25th of April, where is the sun rising, setting, etc. ?
Answer : Rising at Sandwich Islands.

Setting at Cape of Good Hope.

Noon at Nova Scotia, Venezuela, and Buenos

Ayres.
Midnight at Australia and China.

joslin's globes. 23

Problem XIX. Any place in the north frigid zone being
given, to find how long the sun shines there without setting, and
how long he is invisible.

Rule. Rectify the globe for the latitude of the place ; bring the
ascending signs of the ecliptic to the north point of the horizon, and see
what day of the ecliptic is cut by that point ; then from that day the
sun begins to shine without setting. Now bring the descending signs of
the ecliptic to the north point of the horizon, and see what day of the
ecliptic is cut by that point ; then on that day the sun ceases to shine
without setting. By proceeding in the same way with the southern
point of the horizon, we may find the beginning and end of the time
during which the sun is invisible.

EXAMPLES.

How long does the sun shine without setting at Uppernavik
in Greenland, latitude 72?° north, and how long is he in-
visible ?

Answer: It begins to shine continually on the 9th of
May, and ceases to shine continually on the 4th of
August.
The longest day is therefore 87 days long ; that is, the

sun shines without setting for 87 days.
The time during which the sun will be invisible extends

from the 10th of November to February 1.
The longest night is therefore 83 days long ; that is, the
sun is never seen during this 83 days.

Problem XX. To find the beginning, end, and duration
of twilight at any given place on any given day.

Rule. Rectify the globe for the latitude of the place (Problem X.) ;
screw the quadrant of altitude upon the metallic meridian over the given
latitude ; bring the sun's place in the ecliptic on the given day to the
metallic meridian ; set the hour circle at 12 ; turn the globe westward
until the sun's place comes to the western edge of the wooden horizon ;

24 joslin's globes.

then the hour circle "will show the time of the sun's setting and the
beginning of evening twilight. Continue turning the globe until the
sun's place is 18° below the horizon, measured on the quadrant of alti-
tude ; then the hour circle will show the time at which the evening
twilight ends. The duration of twilight is equal to the difference between
the time at which it begins and the time at which it ends.

The time at which evening twilight ends, subtracted from 12, will
give the time of the beginning of morning twilight, which is of the
same length as evening twilight.

EXAMPLES.

Required the beginning, end, and duration of evening and
morning twilight at London on the 23d of September.

Answer: Evening twilight begins at 6 o'clock and ends
at 8 o'clock; duration, 2 hours. Morning twilight
begins at 4 o'clock and ends at 6 o'clock.

Solution: Evening twilight ends 8 h.
" " begins

Duration of twilight

Evening twilight ends

Morning twilight begins
Duration of twilight

Morning twilight ends 6 h.

Required the duration of twilight at Boston on June 1.
Ansiver : 2| hours.

Problem XXI. The suns meridian altitude and the day
of the month being given, to find the latitude of the place.

Rule. Bring the sun's place in the ecliptic to the metallic meridian ;
then, if the sun was south of the observer when the altitude was taken,

6h.

2h.

12 h.

8h.

4h.

2h.

joslin's globes. 25

elevate the sun's place as many degrees above the south point of the
wooden horizon as are equal to the sun's meridian altitude ; the eleva-
tion of the north pole above the horizon will give the latitude of the
place. If the sun was north of the observer when the altitude was
taken, elevate the sun's place as many degrees above the north point of
the horizon as are equal to the sun's meridian altitude ; the elevation of
the south pole will give the latitude of the place.

EXAMPLES.

On the 21st of June the meridian altitude of the sun was
observed to be 69 i°, and south of the observer ; what was the
latitude of the place ?
Answer : 44° north.

December 21 the meridian altitude of the sun was 25°,
and south of the observer ; what was the latitude of the
place ?

Answer : 41 f° north.

May 10 the sun's meridian altitude was observed to be
30° north of the observer ; what was the latitude of the
place ?

Answer : 42?° south.

Problem XXII. To find all places at which a solar or
lunar eclipse is visible at the same instant, the day and hour
being given when it is visible at a certain place.

Rule. Find the place to which the sun is vertical at the given time ;
bring the place to the metallic meridian, and rectify the globe to the
latitude of that place ; then at all places within TO0 of this place an
eclipse of the sun may be visible, especially if it be a total eclipse. If
it be a lunar eclipse, it will be visible to all those places below the
wooden horizon.

26 joslin's globes.

EXAMPLES.

There was an eclipse of the sun October 9, 1847, at 7%
o'clock in the morning, at London ; at what places might it
be visible ?

Answer: London, Hindoostan, Arabia, Egypt, etc.

There was an eclipse of the moon January 26, 1842, at
6 o'clock in the afternoon, at London ; at what places was it
visible ?

Answer: Europe, Africa, part of Asia, and South
America.

There was an eclipse of the moon January 7, 1852, at 6 i
o'clock in the morning, at London ; at what places was it
visible ?

Answer : England, France, Spain, North and South
America.

Problem XXIII. To place the terrestrial globe in the
sunshine at any given place, so that it will represent the actual
position of the earth at that time with respect to the sun.

Rule. Place the globe so that the wooden horizon shall be in a
horizontal position, and its north and south points in a line exactly
north and south, the north to the north ; bring the given place to the
metallic meridian, and rectify the globe to its latitude. All the lines
on the globe are then in the position described under Problem X.

Problem XXIV. To construct a horizontal sun-dial by
the globe for any given latitude.

Rule. Set the globe as in Problem XXII., and bring the first point
of Aries (the meridian of Greenwich) to the metallic meridian. Prepare
a smooth board about 6 inches wider than the diameter of the globe.
On this board describe a circle whose diameter is exactly the same as

joslin's globes. 27

the diameter of the globe. At the extremities of a diameter of this circle
mark a north and south point. Regard these two points as cut by the
plane of the first meridian. Mark the north point 12, which will indi-
cate the hour of noon. With a pair of dividers take the exact distances
between each two meridians, 15° apart, at the points where they are
cut by the horizon, beginning at the north point of the horizon and
going each way. Transfer these distances to the circumference of the
circle on the board, making a point to correspond with each meridian.
Number the points from 12 toward the west 11-10-9 for the morning
hours, and toward the east 1-2-3-4-5 for the evening hours. No more
points may be made than equal the number of hours in the longest day
at the given place. From the centre of the circle draw a radius to each
point in the circumference. In the centre fix a pin inclined toward the
north point, or 12, as many degrees as are equal to the latitude of the
place, and of such length that its shortest shadow will reach the cir-
cumference. This board placed exactly horizontal in the sunshine, with
its north and south points in a line exactly north and south, will con-
stitute a horizontal sun-dial.

Problem XXV. To illustrate the three positions of the
sphere, Right, Parallel, and Oblique, so as to show the
aspect of the sun, etc., at different times of the year.

The Eight Sphere. The people at the equator have this
sphere ; the north, polar star always appears in their horizon.
To place the globe in this position bring the two poles to the
wooden horizon ; turn the globe round ; then the following
facts may be readily shown. At the equator the days are
always 12 hours long, whatever may be the position of the
sun in the ecliptic ; for the sun and all the heavenly bodies
will appear to revolve round the earth in circles parallel to
the equinoctial, and the diurnal arc above the horizon will
always be equal to that which is below it. The whole of the
heavens may be seen at the equator in the course of the day,
and in a year all the stars in the heavens may be seen.

28 joslin's globes.

The Parallel Sphere. The people at the poles, if there were
any, would have this sphere ; at the north pole, the north
polar star would appear exactly overhead. To place the
globe in this position, elevate the north pole 90° above the
horizon, or, what is the same thing, make the equator to
coincide with the wooden horizon. At the poles, during six
months of the year, the- sun shines without setting, and during
the other six months he never appears above the horizon.
At the poles the heavenly bodies appear to move in circles
parallel to the horizon ; they appear to move entirely around
it every 24 hours. The sun appears to move in the form of
a spiral, higher each day, for three months, till he reaches
his greatest declination ; and then, in a similar manner, lower
and lower, for three months, till he goes below the horizon.
But there will be twilight until the sun is 18° below the
horizon. At the poles an observer can see only those stars
that are in his hemisphere. Near the poles the stars do not
set, but appear to revolve around the pole, going down each
day toward the horizon, but never below it.

The Oblique Sphere. All people on the earth, excepting
those at the equator and the poles, have this position of
the sphere. In this case the horizon cuts the equator ob-
liquely. To place the globe in this position, elevate the pole
to the latitude of the place of the observer. Take Boston,
for example, and elevate the north pole to the latitude of
Boston. To the people of Boston, for six months of the year,
the days are more than 12 hours long, and for the other six
months they are less than 12 hours long. On the 21st of
March the sun shines perpendicularly over the equator, and
the days and nights are equal in length all over the globe ;
as the sun's northern declination increases the days increase
in length, for the diurnal arcs described by the sun are un-
equally divided by the horizon. When the sun has attained

joslin's globes. 29

its greatest northern declination, June 21, the days have
attained their greatest length, but they will be the shortest
to the people of the southern hemisphere. After this, the
sun's northern declination gradually decreases, and the days
also decrease in length. When the sun arrives at the autumnal
equinox, September 22, the days and nights are again of
equal length. After this, the days become shorter and shorter
as the sun's southern declination increases, until it has at-
tained its greatest southern declination, December 21. Then
the days will be shortest with us, but longest to the people
of the southern hemisphere. After this, our days increase in
length, and, when the sun again arrives at the vernal equinox,
the days and nights are again equal.

The duration of twilight is greater with us than at the
equator, because with us the diurnal arc of the sun cuts the
horizon obliquely, which causes it to take a longer time to
get 18° below the horizon ; whereas, at the equator, the sun
sinks perpendicularly below the horizon, which shortens the
duration of twilight.

The people that live in the northern hemisphere can never
see those stars which lie toward the south polar star, and the
people in the southern hemisphere can never see those stars
which lie toward the north polar star ; but, as already noted,
a person at the equator may see all the stars in the heavens
in the course of the year.

30 joslin's globes.

THE CELESTIAL GLOBE.

1. The Celestial Globe is constructed to represent the aspect
of the heavens ; all the stars are laid down on its surface
according to their relative situations ; and the various imagi-
nary circles and points upon the terrestrial globe are sup-
posed to be transferred to the celestial one. The rotary
motion of this globe, from east to west, represents the apparent
diurnal motion of the sun and stars to a spectator supposed
to be situated in the centre of the globe.

2. The Latitude and Longitude of a Star or Planet. The lati-
tude of a body on the celestial globe is its distance from the
ecliptic, north or south, measured in degrees on a great
circle passing through the body and the pole of the ecliptic ;
and the longitude is the distance of the point, where the
great circle cuts the ecliptic, from the first point of Aries.
Latitude and longitude are referred to the ecliptic on the
celestial globe, but on the terrestrial globe they are referred
to the equator.

3. The Declination and Eight Ascension of a heavenly body.
The declination of a body is its distance from the equinoctial,
north or south, measured in degrees on a meridian passing
through the body ; and the right ascension is the distance
of the point where this meridian cuts the equinoctial, from
the first point of Aries. The right ascension of a body is
sometimes expressed in hours, making the usual allowance of
one hour of time for 15° of distance.

PEOBLEMS ON THE CELESTIAL GLOBE.

Problem I. To find the right ascension and declination
of the sun or of a star.

Rule. Bring the sun's place in the ecliptic, or the given star, to the
metallic meridian ; the degree over it is the declination, and the degree
on the equator cut by the metallic meridian gives the right ascension.

joslin's globes. 31

EXAMPLES.

1. Required the right ascension and declination of Regulus,
in the constellation of the Lion.

Answer : Right ascension, 150° ; Declination, 12° 47'
north.

Required the right ascension and declination of the fol-
lowing stars : —

2. Oapella, in the constellation of Auriga.

3. Dubhe, " " " the Great Bear.

4. Aldebaran, " " " Taurus.

5. Arcturus, " " Bootes.

Answers :

2. Right Ascension, 76°. Declination, 45° 49' north.

3. " " 163° 15'. " 62° 36' "

4. " " 66°. " 16° 10' "

5. " " 212°. " 20° 3' "

Problem II. The right ascension and declination of a
heavenly body being given, to find its place on the globe.

Rule. Bring the given degree (or given time) of right ascension to
the metallic meridian ; then under the given degree of declination
reckoned on the metallic meridian you will find the place of the body.

EXAMPLES.

1. Required the star whose right ascension is 76° 45', or
5 hours 7 minutes, and declination 8° 24' south.

Answer : Rigal, a star of the first magnitude in the con-
stellation of Orion.

32 joslin's globes.

What stars have the following positions ?

Eight Ascension. Declination.

2. 261° 30' or 17 h. 26 min. 52° 25' north.

3. 6h. 38 min. 16° 29' south.

4. 19 h. 43 min. 8° 26' north.

5. 7 h. 35 min. 28° 26' north.
Answers :

2. Alwaid, in the constellation of Draco.

3. Sirius, " " " the Great Dog.

4. Al Tair, " " " the Eagle.

5. Pollux, " " " the South Twin.

Problem III. To find the latitude and longitude of any
star.

Rule. Bring the pole of the ecliptic to the metallic meridian ; fix
the quadrant of altitude over the pole, and move the quadrant till its
edge comes over the star ; then the degree of the quadrant over the star
is the latitude, and the number of degrees between the edge of the quad-
rant and the first point of Aries, reckoned on the ecliptic, is the longitude.

EXAMPLES.

What is the latitude and longitude of Aldebaran, in the
constellation of Taurus.

Answer: Latitude, 5° 28' 'south. Longitude, 2 signs,
6° 53'.

What is the latitude and longitude of Pollux in Gemini ?
Answer : Latitude, 6° 30' north. Longitude, 3 signs, 21°.

Problem IV. The day and hour and the latitude of the
place being given, to place the celestial globe so as to represent
the appearance of the heavens at that place and time.

Rule. Rectify the globe to the latitude of the place ; bring the sun's
place in the ecliptic to the metallic meridian ; set the hour circle to 12

joslin's globes. 33

(recollect this is 12 noon) ; turn the globe till the hour circle points to
the given hour of the day ; then in this position the stars figured on the
globe will exactly correspond with the actual appearance of the stars in
the heavens.

Problem V. The day and hour and the latitude of the
place being given, to find what stars are rising, setting, and
culminating.

Rule. Rectify the globe for the latitude of the place ; bring the
sun's place in the ecliptic to the metallic meridian ; put the hour circle
to 12 noon ; turn the globe till the hour circle indicates the given hour
of the day : then all the stars on the eastern semicircle will be rising ;
those on the western semicircle will be setting ; those under the metallic
meridian will be culminating, or in their southing ; and the stars above
the wooden horizon will be visible at the given time and place.

To determine those stars which never set. Turn the globe on its axis ;
then those stars which do not go below the wooden horizon never set at
the given place.

EXAMPLES.

To find the constellations which are rising, setting, and
culminating, on January 20, at 2 o'clock in the morning, at
London.

Answer: The constellations of Lyra, etc., are rising;
Andromeda, etc., are setting; and the Great Bear, etc.,
are on the meridian.

To find the stars which are rising, setting, and culminating,
on the 8th of February, at 9 o'clock in the evening, at
London.

Answer : Alpheta, in the Northern Crown, is rising ;
Arcturus, in Bootes, is a little above the horizon;
Sirius is on the meridian; Markab, in Pegasus, is just
below the western horizon.

34

Problem VI. To find the time when any star will rise,
come to the meridian, and set, on any given day, at any given
place.

Rule. Rectify the globe to the latitude of the place ; bring the
sun's place in the ecliptic to the metallic meridian ; set the hour circle
to 12 noon ; turn the globe till the given star comes to the eastern edge
of the wooden horizon ; then the hour circle will show the time of rising:
turn the globe till the star comes to the metallic meridian, and the hour
circle will show the time of its culminating, or southing ; turn the globe
till the star comes to the western edge of the wooden horizon, and the
hour circle will show the time of setting.

EXAMPLES.

At what time will Arcturus, in the constellation of Bootes,

rise, culminate, and set, at London, on the 7th of September?

Answer : Arcturus will rise at 7 o'clock in the morning,

culminate at 3 o'clock in the afternoon, and set at 11

o'clock at night.

At what time will Aldebaran, in the constellation of
Taurus, rise, culminate, and set, at Edinburgh, on Nov. 26 ?
Answer: Aldebaran will rise at 4? o'clock in the after-
noon, culminate at 12£ o'clock at night, and set at
8 o'clock the next morning.

Problem VII. The day of the month, the latitude of the
place, and the altitude of a star being given, to find the hour
of the night.

Rule. Rectify the globe to the latitude of the place ; bring the sun's
place in the ecliptic to the metallic meridian ; set the hour circle to 12
noon ; screw the quadrant of altitude to the zenith, and turn it to that
side of the meridian on which the star was observed ; move the globe
and the quadrant till the star is on the degree of the quadrant equal to
the given altitude ; then the hour circle will show the hour required.

joslin's globes. 35

EXAMPLES.

At Rome, on December 2, the star Capella, in the con-
stellation of Auriga, was observed to be 42° above the horizon ;
required the hour.

Answer : 5 o'clock in the morning.

At London, on December 29, the star Deneb, in the tail of
the Lion, was found to be 40° above the horizon and east of
the meridian ; required the hour.

Answer : About 2.15 o'clock in the morning.

Problem VIII. Given the year and the day, to find the
place of a planet on the globe.

Rule. Bring the sun's place in the ecliptic to the metallic meridian ;
set the hour circle to 12 noon ; find in the Nautical Almanac the time
when the planet passes the meridian on the given day, and turn the
globe till the index of the hour circle points to the hour thus found ;
find in the Almanac the declination of the planet for the same day ;
then, under this declination, found on the metallic meridian, is the place
of the planet.

36

JOSLINS GLOBES.

Style 3.

Joslin's Bronze Pedestal Stand.

joslin's globes. 37

JOSLIN'S BRONZE PEDESTAL STAND.

Style 3.

Mounted in this manner, the globe is brought to a con-
venient height for use while sitting, and, at the same time,
presents an ornamental appearance, adapting it to the parlor
and library as well as to the school-room. It is furnished
with horizon, graduated full brass nickel-plated meridian,
hour dial, etc.

The stand is of bronzed iron, and of such design as to com-
bine great strength with light weight and symmetrical ap-
pearance. Being mounted upon brass castors, can be readily
moved to any position.

PRICES.

18-inch Globe, 43 inches high . . . §80.00

16 " " 42£ " ... 62.50

12 " " 381 " . ■" ... 37.50

Globe with Celestial Map, same price.

-y\ JG/vi£jt/? c>1 aXX 3/-

38

JOSLIN S GLOBES.

Style 6.

Joslin's Tripod Stand.

joslin's globes. 39

JOSLIN'S TRIPOD STAND.

Style 6.

This style of mounting was gotten up particularly for
parlor and library use, many persons objecting to an iron
stand. It makes a very light, strong, and ornamental stand,
and will look well with any furniture. The arms that sup-
port the ball and horizon are japanned and decorated, and
pivoted the same as in all rotary globes. The legs are
japanned with a little decorating, and screw into the socket
supporting the arms by a polished brass cap-piece fastened
to their top.

PRICES.

18-inch Globe $78.00

16 " 60.00

12 " 37.50

Globe with Celestial Map, same price.

40

JOSLIN S GLOBES.

JOSLIN'S LOW BRONZE STAND.

Style 4.

This style, with black walnut horizon, graduated full brass
meridian, hour dial, etc., is mounted upon a light bronzed
stand of neat and appropriate design.

The arms which support the horizon are pivoted to the
base, thus allowing any portion of the globe to be turned to
the student without changing the position of the base itself,
a very desirable arrangement.

PRICES.

16-inch Globe
12 "
10 "

00
25.00
18.00

Globe with Celestial Map, same price.

JOSLINS GLOBES.

41

JOSLIN'S FULL WOOD STAND.

Style 5.

Mounted upon a substantially made cherry wood stand,
with horizon, graduated full brass meridian, hour dial, and
index, this globe has all the appliances for use in the solution
of problems. It is well adapted to all grades of schools.

PRICES.

16-inch Globe $45.00

12 " 22.00

10 " 17.00

6 " " . . . . . . 10.00

Globe with Celestial Map, same price.

42 joslin's globes.

JOSLIN'S LOW TRIPOD STAND.

Style 8.

Mounted upon three light, neat, bronzed iron legs (prevent-
ing any shrinking and coming apart, as sometimes happens in
wooden stands), with black walnut horizon, graduated full
brass meridian, hour dial, and index. Everything is as accu-
rate as in the highest priced globe ever made.

PRICES.

12-inch Globe $22.00

10 " 17.00

Globe with Celestial Map, same price.

JOSLINS GLOBES.

43

JOSLIN'S SEMI-CIRCLE STAND.

Style 1.

Polished black walnut stand, with graduated brass semi-
meridian. For those who use the globe for reference only, and
who never desire to work problems, this style is neat and most
appropriate.

PRICES.

12-inch Globe $17.00

10 " 12.00

6 " " 5.00

Globe with Celestial Map, same price.

44

JOSLINS GLOBES.

JOSLIN'S TELLURIC GLOBE.

This style was specially designed to furnish a simple means
of illustrating the causes of the Changes of the Seasons and of
the numerous other phenomena which are related to them.
Their success in accomplishing this much desired end is fully
attested by the high commendations of teachers from all
sections of the country.

Each globe is accompanied with a printed manual of 30
pages, giving a complete description of the globe and its
various uses, with illustrative problems.

PRICE.

6-inch Globe

. $15.00

PAMPHLET BINDERS

This is No, 1525

also carried in stock in the following sizes

HIGH WIDE THICKNESS

1529 12 inches 10 inches H inch

1530 12 " 9H "

1932 13 " 10

1933 14 " 11

1934 10 " 12

HIGH WIDE THfCKNESS

1523 9 inches 7 inches /i inch

1524 10 " 7 "

1525 9 " 6

1526 9M " 1Ys "

1527 103^ " 7H "

1528 11 " 8

Other sizes made to order

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